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The preceding Fourier pair can be used to show that
|
(B.35) |
Proof: The inverse Fourier transform of
sinc
is
In particular, in the middle of the rectangular pulse at
, we have
|
(B.36) |
This establishes that the algebraic area under
sinc
is
1 for every
. Every delta function (impulse) must have this
property.
We now show that
sinc
also satisfies the sifting
property in the limit as
. This property fully
establishes the limit as a valid impulse. That is, an impulse
is any function having the property that
|
(B.37) |
for every continuous function
. In the present case, we need to
show, specifically, that
|
(B.38) |
Define
sinc
. Then by the power theorem
(§B.9),
|
(B.39) |
Then as
, the limit converges to the algebraic area
under
, which is
as desired:
|
(B.40) |
We have thus established that
|
(B.41) |
where
sinc |
(B.42) |
For related discussion, see [36, p. 127].
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