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Referring to Fig.9.15, the velocity
transmittance from string 1 to string 2 may be defined as
By physical symmetry, we expect the transmittance to be the same in
the opposite direction:
.
Assuming the incoming wave
on string 2 is zero, we have
, which we found in Eq.(9.16):
Thus, the mass transmittance for velocity waves is
We see that
corresponds to
, as befits a
rigid termination. As
, the transmittance becomes 1 and the
mass has no effect, as desired.
We can now refine the picture of our scattering junction
Fig.9.17 to obtain the form shown in
Fig.9.18.
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