Assume the speed of sound in air is 345 m/s. Then the speed of sound in water is 345 * 5 = 1725 m/s. Use snd to read the time difference between the two impulses. The time difference between the impulses is .012 seconds. Solve using the equation: distance = velocity * time d = vt d = 1725 m/s * .012 s d = 20.7 m The boats are about 20.7 meters apart or approximately 67 feet.