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Convolution Theorem

The convolution theorem for z transforms states that for any (real or) complex causal signals $ x$ and $ y$ , convolution in the time domain is multiplication in the $ z$ domain, i.e.,

$\displaystyle \zbox {x\ast y \;\leftrightarrow\; X\cdot Y}
$

or, using operator notation,

$\displaystyle {\cal Z}_z\{x \ast y\} \;=\; X(z)Y(z),
$

where $ X(z)\isdef {\cal Z}_z(x)$ , and $ Y(z)\isdef {\cal Z}_z(y)$ . (See [84] for a development of the convolution theorem for discrete Fourier transforms.)



Proof:

\begin{eqnarray*}
{\cal Z}_z(x\ast y) &\isdef & \sum_{n=0}^{\infty}(x\ast y)_n z^{-n} \\
&\isdef & \sum_{n=0}^{\infty}\sum_{m=0}^{\infty}x(m) y(n-m) z^{-n} \\
&=& \sum_{m=0}^{\infty}x(m) \underbrace{\sum_{n=0}^{\infty}y(n-m) z^{-n}}_{z^{-m}Y(z)} \\
&=& \left(\sum_{m=0}^{\infty}x(m) z^{-m}\right)Y(z)\quad\mbox{(by the Shift Theorem)}\\
&\isdef & X(z)Y(z) % \quad\pfendmath
\end{eqnarray*}

The convolution theorem provides a major cornerstone of linear systems theory. It implies, for example, that any stable causal LTI filter (recursive or nonrecursive) can be implemented by convolving the input signal with the impulse response of the filter, as shown in the next section.


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``Introduction to Digital Filters with Audio Applications'', by Julius O. Smith III, (September 2007 Edition)
Copyright © 2023-09-17 by Julius O. Smith III
Center for Computer Research in Music and Acoustics (CCRMA),   Stanford University
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