Brett Lockspeiser
blocks@stanford.edu
Music 220a HW1
Eyeballing the waveforms of the two recorded sounds, it looks to me that
the beginning of each impulse happens at the following times:
boat one: .216 sec
boat two: .224 sec
meaning that it took .008 seconds for the sound to travel from the
microphone of one boat to that of the other. We know that the speed of
sound in air is 1,128 feet/sec, and that it is five times that speed in
water, making a speed of 5,640 feet/sec. Using the following equation
involving the distance, the velocity and the time we can solve for
distance since we know both velocity and time:
d = v * t = 5,640 * .008 = 45.120 feet between the microphones on the two
boats.