Brett Lockspeiser
blocks@stanford.edu

Music 220a HW1

Eyeballing the waveforms of the two recorded sounds, it looks to me that the beginning of each impulse happens at the following times:

boat one: .216 sec
boat two: .224 sec

meaning that it took .008 seconds for the sound to travel from the microphone of one boat to that of the other. We know that the speed of sound in air is 1,128 feet/sec, and that it is five times that speed in water, making a speed of 5,640 feet/sec. Using the following equation nvolving the distance, the velocity and the time we can solve for distance since we know both velocity and time:

d = v * t = 5,640 * .008 = 45.120 feet between the microphones on the two boats.